Angle Between Two Tangents : Form an external point we can draw two tangents to a circle. In the figure we have an external point P we can draw two tangents PA and PB .APB is the angle between two tangents,
ILLUSTRATION: Prove that the angle between two tangents drawn from an external point to a circle is supplementary to the angle subtended by the line segments joining the points of contact at the centre. Solution In fig., PA and PB are two tangents to the circle from an external point P. Join OA and OB. We know that the tangent makes an angle of with the radius
Also, sum of the angles of a quadrilateral is . Therefore, Thus, is supplementary to the angle . |
ILLUSTRATION: In the figure prove that PQR is an equilateral triangle where O and P are centre points of the circles SOLUTION: PA and PB are tangents from point P to the circle with centre O [tangent makes a right angle with radius] Also, OAPB is a quadrilateral and sum of the angles of a quadrilateral is . Therefore, As [Given ]
Now PQR is an isosceles triangle as PQ = PR [ radii of the circle with centre P] [Angles opposite to equal sides are equal] Also [Angle sum property of triangle PQR] As all the angles of PQR are , Therefore PQR is an equilateral triangle. |
If tangents PA and PB from a point P to a circle with centre O are inclined to each other an angle of 70° , then find ∠POA. | |||
Right Option : C | |||
View Explanation |
In the given figure, PA and PB are tangents from P to a circle with centre O. If ∠AOB = 130°, then find ∠APB | |||
Right Option : C | |||
View Explanation |
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